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Linear
C
n
D
n
S
n
A
n
...
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degree
Characters
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⋊
.
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Extensions
1→N→G→Q→1 with N=
C
2
3
×C
4
and Q=
C
15
Direct product G=N×Q with N=
C
2
3
×C
4
and Q=
C
15
d
ρ
Label
ID
C
2
3
×C
60
480
C2^3xC60
480,1180
Semidirect products G=N:Q with N=
C
2
3
×C
4
and Q=
C
15
extension
φ:Q→Aut N
d
ρ
Label
ID
(C
2
3
×C
4
)⋊C
15
=
A
4
×C
2
×C
20
φ:
C
15
/
C
5
→
C
3
⊆ Aut
C
2
3
×C
4
120
(C2^3xC4):C15
480,1126
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